Power Generation MCQs Part 14

Power Generation MCQs Part 14

Overall efficiency of a steam power station is given by

Overall efficiency of a steam power station is given by:

1. Overall efficiency = Thermal Efficiency * Electrical efficiency
2. Overall efficiency = Thermal Efficiency * Mechanical efficiency
3. Overall efficiency = Thermal Efficiency * Prime mover efficiency
4. None of these

Correct answer: 1. Overall efficiency = Thermal Efficiency * Electrical efficiency

The penstock, turbine and generator efficiencies of a hydroelectric power plant are 95, 90, and 85 respectively. The overall efficiency of plant is:

The penstock, turbine and generator efficiencies of a hydroelectric power plant are 95, 90, and 85 respectively. The overall efficiency of plant is:

1. 62.7%
2. 72.7%
3. 82.7%
4. 92.7%

Correct answer: 2. 72.7%

Solution:

Overall η = η (penstock) * η (turbine) * η (generator)

Overall η = 0.95 * 0.9 * 0.85 = 0.72675 = 72.7%

The ideal load factor should be

The ideal load factor should be:

1. 0.3
2. 0.5
3. 0.8
4. 1

Correct answer: 4. 1

One atomic mass unit is equivalent to:

One atomic mass unit is equivalent to:

1. 210.3 MeV
2. 455.6 MeV
3. 822.4 MeV
4. 931.4 MeV

Correct answer: 4. 931.4 MeV

A power system has a connected load of 120 kW, maximum load of 100 kW, Base load of 25 kW and avera

A power system has a connected load of 120 kW, maximum load of 100 kW, Base load of 25 kW and average load of 50 kW. The load factor is:

1. 0.4
2. 0.5
3. 0.6
4. 0.7

Correct answer: 2. 0.5

Explanation: Load factor = Average load/Maximum demand = 50 kW/100 kW = 0.5