Power Generation MCQs Part 14

Power Generation MCQs Part 14

Overall efficiency of a steam power station is given by

Overall efficiency of a steam power station is given by:

  1. Overall efficiency = Thermal Efficiency * Electrical efficiency
  2. Overall efficiency = Thermal Efficiency * Mechanical efficiency
  3. Overall efficiency = Thermal Efficiency * Prime mover efficiency
  4. None of these

Correct answer: 1. Overall efficiency = Thermal Efficiency * Electrical efficiency

The penstock, turbine and generator efficiencies of a hydroelectric power plant are 95, 90, and 85 respectively. The overall efficiency of plant is:

The penstock, turbine and generator efficiencies of a hydroelectric power plant are 95, 90, and 85 respectively. The overall efficiency of plant is:

  1. 62.7%
  2. 72.7%
  3. 82.7%
  4. 92.7%

Correct answer: 2. 72.7%

Solution:

Overall η = η (penstock) * η (turbine) * η (generator)

Overall η = 0.95 * 0.9 * 0.85 = 0.72675 = 72.7%

The ideal load factor should be

The ideal load factor should be:

  1. 0.3
  2. 0.5
  3. 0.8
  4. 1

Correct answer: 4. 1

One atomic mass unit is equivalent to:

One atomic mass unit is equivalent to:

  1. 210.3 MeV
  2. 455.6 MeV
  3. 822.4 MeV
  4. 931.4 MeV

Correct answer: 4. 931.4 MeV

A power system has a connected load of 120 kW, maximum load of 100 kW, Base load of 25 kW and avera

A power system has a connected load of 120 kW, maximum load of 100 kW, Base load of 25 kW and average load of 50 kW. The load factor is:

  1. 0.4
  2. 0.5
  3. 0.6
  4. 0.7

Correct answer: 2. 0.5

Explanation: Load factor = Average load/Maximum demand = 50 kW/100 kW = 0.5

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