Basic Electrical Engineering MCQs Part 9

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Basic Electrical Engineering MCQs Part 9

The time required for 2 kW heater for raising temperature of 10 litres of water through 10°C is

The time required for 2 kW heater for raising temperature of 10 litres of water through 10°C is:

  1. 185 s
  2. 210 s
  3. 420 s
  4. 520 s

Correct answer: 2. 210 s

Solution:

From equation

m * S * T = P * t

Where

m = mass in gram = 10 * 1000 = 10000 gram

—————-

T = Temperature difference = 10°C

S = Specific heat = Energy required in joules to raise temp of 1 gram of mass by 1 degree celsiuc.

In case of water S = 4.186 joules/gram/°C

P = Power of heater = 2 kW = 2000 watt = 2000 joules/sec

t = time is second

—————-

t = (m*S*t)/P = (10000 * 4.186 * 10)/1000 = 210 sec

A heater coil rated at 1200 W, 220 V is connected to 100 V line. The power consumed is

A heater coil rated at 1200 W, 220 V is connected to 100 V line. The power consumed is:

  1. 139.22 W
  2. 247.9 W
  3. 315.4 W
  4. 448.9 W

Correct answer: 2. 247.9 W

Solution:

R = V²/P = 220²/1200 = 40.3 Ω

Power consumed at 100 V = (100)²/40.33 = 247.9 W

A 8°C rise in temperature is observed in a conductor by passing current. When current is doubled, the rise in temperature will be

A 8°C rise in temperature is observed in a conductor by passing current. When current is doubled, the rise in temperature will be:

  1. 8°C
  2. 16°C
  3. 32°C
  4. 64°C

Correct answer: 3. 32°C

Solution:

From equation: H ∝ I²

———————-

H2/H1 = (2I/I)² = 4

———————-

Now  θ ∝ H

θ2/θ1 = H2/H1 = 4

θ2 = 4θ1 = 4 * 8 = 32°C

An electric heater, kettle, and oven are all rated at 1 kW, 230 V. Which of them has highest resistance

An electric heater, kettle, and oven are all rated at 1 kW, 230 V. Which of them has highest resistance:

  1. Heater
  2. Kettle
  3. Oven
  4. All have equal resistance

Correct answer: 4. All have equal resistance

Explanation: From formula R = V²/P, since all have same voltage and power ratings, all will have same resistance.

Certain tap supplies water at 20°C. A man takes 1 liter of water per minute at 39°C from geyser. The power of geyser is (Consider efficient to be 100%

Certain tap supplies water at 20°C. A man takes 1 liter of water per minute at 39°C from geyser. The power of geyser is (Consider efficient to be 100%:

  1. 985 W
  2. 1330 W
  3. 1485 W
  4. 1965 W

Correct answer: 2. 1330 W

Solution:

Heat output of device in joules per second is the power of device.

Power of geyser = mc θ * 4.2 joules.sec = 1000/ * 1 * (39 – 20 ) = 1330 W

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